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Lena [83]
3 years ago
8

What is the correct decimal expansion for 2 1/11 ​? A. 2.09 B. 2.57 C. 2.09 D. 2.11

Mathematics
1 answer:
hjlf3 years ago
3 0

Your choices A and C are the same

but the decimal of 1/11 is 0.090909

so your answer would be 2.09

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Simplify the inequality​
Novosadov [1.4K]

Answer:

2x + 4 > 14

2x > 10

<u>x > 5</u>

6 0
3 years ago
Read 2 more answers
24 = -6 (m+1) + 18 <br><br> What is the answer?
Nataly_w [17]

Answer:

m = -2

Step-by-step explanation:

<em>Distribute first.</em>

24 = -6(m+1) + 18

24 = -6m - 6 + 18

<em>Then you combine like terms.</em>

24= -6m + 12

<em>Then you still combine like terms. You subtract 12 from each side.</em>

24 = -6m + 12

-12            - 12

12= -6m

<em>Then divide by -6 to isolate the variable.</em>

12 = -6m

/-6     /-6

-2 = m

<em />

8 0
4 years ago
What is the initial value in the exponential equation below?<br><br> y =<br><br> = 4000(1.05)*
Svet_ta [14]

Answer:

y = 4000 (when x = 0)

Step-by-step explanation:

The initial value of the exponential equation is:

y = 4000\cdot (1.05)^{0}

y = 4000\cdot 1

y = 4000

8 0
3 years ago
Jason jumped off a cliff into the ocean in Acapulco while vacationing with some friends. His height as a function of time could
WINSTONCH [101]

Answer:

484feet

Step-by-step explanation:

If the height as a function of time could be modeled by the function h(t)=−16t^2 +16t+480, where t is the time in seconds and h is the height in feet.

The maximum height of Jason occurs when dh/dt = 0 (velocity is zero)

dh/dt = -32t + 16

0 = -32t + 16

32t = 16

t = 16/32

t = 1/2

t = 0.5secs

Get the maximum height

Recall that h(t)=−16t^2 +16t+480

Substitute t = 0.5

h(0.5)=−16(0.5)^2 +16(0.5)+480

h(0.5) = -4 + 8 + 480

h(0.5) = 4 + 480

h(0.5) = 484

Hence the maximum height reached by Jason is 484feet

5 0
3 years ago
Solve the system of equations y=3x. <br> y=x^2-4
aleksandr82 [10.1K]

Answer:

  (x, y) = (-1, -3)  or  (4, 12)

Step-by-step explanation:

A graphing calculator can show the solutions to this system.

__

You can equate expressions for y and solve for x.

  3x = x^2 -4

  x^2 -3x = 4 . . . . add 4-3x

  x^2 -3x +2.25 = 6.25 . . . . complete the square by adding (-3/2)^2 where -3 is the coefficient of x.

  (x -1.5)^2 = 2.5^2 . . . . . . rewrite as squares

  x -1.5 = ±2.5 . . . . . . . . . . take the square root

  x = 1.5 ± 2.5 = -1, +4

  y = 3x = -3, +12, respectively

Solutions are ...

  (x, y) = (-1, -3) . . . . and . . . . (4, 12)

8 0
3 years ago
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