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tensa zangetsu [6.8K]
3 years ago
10

Sandra has ribbons that are 2/6 meter 3/4meter and 4/9 meter long .She needs to use the ribbon longer than 2/3meter to make a bo

w. Which length of ribbon can she use for the bow?
Mathematics
2 answers:
timurjin [86]3 years ago
6 0

Answer:

3/4 meter

Step-by-step explanation:

Need Common denominators to compare size

2/6  3/4  4/9     which is longer than 2/3?

2/6 compared to 2/3.  2/6 = 2/6 and 2/3 = 4/6.  

2/6 < 2/3 so 2/6 is too short

3/4 compared to 2/3   3/4 = 9/12  and 2/3 =  8/12

3/4 > 2/3 so 3/4 is longer than 2/3

4/9 compared to 2/3  4/9 = 4/9 and 2/3 = 6/9

4/9 < 2/3 so 4/9 is too short

bonufazy [111]3 years ago
3 0
Correct answer: She can use the bow with the length of 3/4

Explanation: when you divide 2/3 you get a continuous 0.6 so now you know that when you divide the rest of the lengths you need to find the answer which length is greater than 0.6. For example, 2/6 (2 divided by 6) = 0.3 so that is out. 4/9 (4 divided by 9)= 0.4 so that is out as well and as for 3/4 (3 divided by 4)= 0.75 which is greater than 0.6 and makes your answer of 3/4 correct.

Have a great day :)
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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

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