Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer:
median 88 first 84 third 92
Step-by-step explanation:
Answer:
12.6 square feet
Step-by-step explanation:
So first we set it up:
18ft is 100% of the original
and the area of the copies are 70%
Copies: x
x/70 = 18/100
70(18) = 1260
1260/100 = 12.6
x = 12.6
Simplifying
4x + -3y = 12
Solving
4x + -3y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3y' to each side of the equation.
4x + -3y + 3y = 12 + 3y
Combine like terms: -3y + 3y = 0
4x + 0 = 12 + 3y
4x = 12 + 3y
Divide each side by '4'.
x = 3 + 0.75y
Simplifying
x = 3 + 0.75y