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aniked [119]
3 years ago
9

Can someone explain how to do this, please?​

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

\sqrt{ {28x}^{2} - 6x }

Step-by-step explanation:

You would substitute "2x" for every "x" in the function in the same way you would substitute any other number.

So if f(x)=Sqrt[7x²-3x], then: f(2x)=Sqrt[7(2x)²-3(2x)]

=Sqrt[7(4x²)-3(2x)]

=Sqrt[28x²-6x]

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In 2007, there were 31 laptops
abruzzese [7]

Answer:

l=31+20(y-2007)

where l is the number of laptops, and y is the year.

in 2017: l=231

Step-by-step explanation:

I will define the variable x as the number of years that passed since 2007.

Since the school buys 20 lapts each year, after a number x of years, the school will have

20*x more laptops.

and thus, since the school starts with 31 laptops, the equation to model this situation is

l=31+20*x

where l is the number of laptops.

since x is the number of years that have passed since 2007, it can be represented like this:

x=y-2007

where y can be any year, so the equation to model the situation using the year:

l=31+20(y-2007)

and this way we can find the number of laptos at the end of 2017:

y=2017

and

l=31+20(y-2007)

l=31+20(2017-2007)\\l=31+20(10)\\l=31+200\\l=231

3 0
3 years ago
0.009 ia 1/10 of what number?
d1i1m1o1n [39]
0.009 x 10 = 0.09

it may not be correct, but here you go.
3 0
3 years ago
Read 2 more answers
Which of the following statements is not correct?
aleksandr82 [10.1K]
That the last one
A parallelogram is not always a rectangle
3 0
3 years ago
-8(x + 1) + 3(x - 2) = -3x + 2?
alexira [117]
First you need to distribute the -8
So you would get -8x-8 now distribute the 3 so it would be 3x-6
-8x-8+3x-6=-3+2 is how it should look
Now combine the -8x and 3x cause their like terms and also -8 and -6
-5x-14=-3x+2 now add -3 to both sides
-2x-14=2 and add 14 to both sides
-2x=12 all left to do is divide both by -2
X=-6
8 0
3 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
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