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Cerrena [4.2K]
3 years ago
15

Please help with this question.

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

10

Step-by-step explanation:

see attachment

If you do it by hand, then you set y = 0, factor and solve

Download docx
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A researcher selects a random sample of size n from a population and uses the collected data to compute a 95% confidence interva
Karo-lina-s [1.5K]

Answer:

I wish I know the answer

Step-by-step explanation:

lemme try again

7 0
3 years ago
I’m confused on this and i just moved from schools so
Elina [12.6K]

Answer:

(-2,3)

Step-by-step explanation:

The point where two lines cross should be your answer!!!

(-2,3) is where the two lines meet/cross!!

That is the definition of a system on a graph!

-Where two lines meet/cross!!

6 0
2 years ago
Donna is running a track it takes her 10 minutes to run 6 laps if she keeps running at the same speed how long will it take her
kaheart [24]
To solve this problem we can make a proportion.
6      5
-- = ---
10    x

to solve this proportion we can cross multiply and divide.
5 times 10 is 50.  divided by 6 is 8.3
it will take her 8.3 minutes to run 5 laps
7 0
3 years ago
Read 2 more answers
Solve 4(x + 6) = 2(2x + 12)
Andru [333]

Answer:

Infinitely many solutions

Step-by-step explanation:

4(x+6)=2(2x+12)

4(x+6)=2(2(x+6))

4(x+6)=4(x+6)

Infinitely many solutions

3 0
3 years ago
Read 2 more answers
Tony wants to calculate his average quiz score. The formula gives Tony’s average score A for a total of T points on n quizzes. T
Gnoma [55]
In calculating the average score, add the scores of each person and then divide it by the number of scores present. In this problem, Tony has forty seven points for five different quizzes. You are required to calculate for the average score of Tony. The formula is A = T/n, where A is the average score, T is the score, and n is the number of quizzes.  

A = T/n
A = 47/5
<u>A = 9.4</u> <span>               
Therefore, Tony has an average of 9.4 points in five different quizzes. </span>
6 0
3 years ago
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