Answer:
2a^2b(5a-3b)
If not then the other way is
5a-3b
Step-by-step explanation:
The GCF of 10a^3b and -6a^2b^2 is 2a^2b
So divide by that you will get
2a^2b(5a-3b)
Answer:
What are you trying to do to my brain?
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
287 people said they did unless you want decimals its 286.65
Answer:155in^2
Step-by-step explanation:
Area of the poster board that she has left=Area of ||gm- area of ∆
Area of the poster board that she has left= 10*20-1/2*9*10
Area of the poster board that she has left=200-45=155in^2
