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andriy [413]
3 years ago
14

The price of a pair of shoes is $45.90. The sales tax rate is 5%. How much sales tax do you need to pay?

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

The sales tax to be paid for the pair of shoes is $2.29.

Step-by-step explanation:

If the price of a pair of shoes is $45.90, and the sales tax rate for it is of 5%, in order to know the sales tax to be paid we have to do the following calculation:

(45.90 x 5) / 100 = X

229.5 / 100 = X

2.295 = X

So, as we can see, the sales tax to be paid is $2.29

Ne4ueva [31]3 years ago
5 0
Multiply the price by the 5% by turning the percent into a decimal.
5% = 0.05
45.90 x 0.05 = $2.295
Which can be rounded to 2.30 if needed.
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The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Jadas family has completed 30% of a trip. They have traveled 15 miles. How far is the trip
valentina_108 [34]

Answer:

50

Step-by-step explanation:

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x=50

8 0
3 years ago
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4x-5 - 2x-1
3241004551 [841]

Answer:

\frac{5x - 8}{3}

Step-by-step explanation:

Find the LCM of the denominators and then solve:

\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\

\frac{4x - 5}{2} - \frac{2x - 1}{6} \\\\\frac{3(4x - 5) - 2x - 1}{6} \\\\\frac{12x - 15 - 2x - 1}{6}\\\\\frac{10x - 16}{6}\\\\ \frac{2(5x - 8)}{2 * 3} \\\\ \frac{5x - 8}{3}

4 0
3 years ago
-3.6,-5.4,-8.1,-12.15 arithmetic or geometric or neither.
Brums [2.3K]

Answer:

Geometric Sequence

Step-by-step explanation:

1. Check the difference.

The difference between the 1st and 2nd term

( - 5.4) - ( - 3.6) =  - 1.8

The difference between the 2nd and 3rd term

( - 8.1) - ( - 5.4) =  - 2.7

The difference is not the same. Therefore, it is not an arithmetic sequence.

2. Check the ratio

The ratio between the 1st and 2nd term

( - 5.4) \div ( - 3.6) = 1.5

The ratio between the 2nd and 3rd term

( - 8.1) \div ( - 5.4) = 1.5

The ratio is the same. Therefore, it is a geometric sequence.

8 0
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The output is 4 less than twice the input
Radda [10]

Answer:

2

because ans = 4. and input =half so,4/2 .=2

5 0
3 years ago
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