Answer:
Part A: The rate of change was greater in case of the graph.
Part B: The figure shows the graph of function A in Redline and Function B in blue line
Part C : Initial value of function B is greater than Function A.
Step-by-step explanation:
Here, Function A show graph of a line and Function show table show a set of value of x and y.
Part A). Which function show greater rate of change.
The slope of line is given by m = 
For function A:
Given graph passes through points (04) and (2,12)
The slope of line is m=
=
= 4
For function B:
Given the table has points (012) and (2,14)
The slope of line is m=
=
= 1
Therefore, The rate of change was greater in case of graph.
Part B). Plot the graph of a function B onto the graph of a function A
The figure shows the graph of function A in Redline and Function B in blueline
Line of function A is more tilted toward the y-axis than Line of function B.
Therefore, Rate of change of function A is greater than Function B.
Part C). Which function has greater initial value?
For function A:
From the graph of part B,
When x=0 y=4
For function B:
From the graph of part B,
When x=0 y=12
Therefore, Initial value of function B is greater than Function A.