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EleoNora [17]
3 years ago
12

Help plz I'm desperate ​

Mathematics
1 answer:
lutik1710 [3]3 years ago
7 0

<u>Anna:</u>

1st month = 18 + \frac{3}{4} = 18\frac{3}{4} inches

2nd month = 18\frac{3}{4} + \frac{3}{4} = 19\frac{1}{2}

3rd month = 19\frac{1}{2} + \frac{3}{4} = 20\frac{1}{4}

4th month = 20\frac{1}{4} + \frac{3}{4} = 21

5th month = 21 + \frac{3}{4} = 21\frac{3}{4}

<u>Grace:</u>

Because Anna is \frac{9}{4} inches shorter than Grace, we can start the count from the third month:

1st month = 20\frac{1}{4}

2nd month = 21

3rd month = 21\frac{3}{4}

4th month = 21\frac{3}{4} + \frac{3}{4} = 22\frac{1}{2}

5th month = 22\frac{1}{2} + \frac{3}{4} = 23

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\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300

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