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2 years ago

Graph a rational function

Mathematics

1 answer:

olga55 [171]2 years ago

6 0

G(x) = {(x-3)(x-2)} / {2(x^2-5)}

Asymptote at x = 5^0.5

Zeros at x = 3 & x = 2

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Use the table to answer the question below.

alexandr1967 [171]

Answer:

c: f(x) = 2(4^x)

Step-by-step explanation:

the table shows that the function is exponential rather than linear.

3 0

2 years ago

Read 2 more answers

2(x/8 + 3) = 7 + 1/4x what is x

malfutka [58]

Answer:

x1 = 2 - $\sqrt{5}$

x2= 2 + $\sqrt{5}$

Step-by-step explanation:

x/4 + 6 = 7 + 1/4x

(x^2 - 1)/4x = 1

x^2 - 1 = 4x

x^2 - 4x -1 = 0

x= (4+ $\sqrt{20}$ )/2 = 2 - $\sqrt{5}$

x= 2 + $\sqrt{5}$

5 0

2 years ago

6y - 5x = 5 and x= 2y + 7

jolli1 [7]

Y = -10 and x = -13 (substitute 2y + 7 for x)

5 0

3 years ago

Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

8 0

2 years ago

Which one is right ?

sergey [27]

Answer:

6/10

Step-by-step explanation:

all can be reduced to 2/5, except 6/10:

2/5

8/20=2/5 (divide out 4)

12/30=2/5 (divide out 6)

but not

6/10 = 3/5!

7 0

2 years ago