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lys-0071 [83]
3 years ago
8

What is the standard equation of the circle in the graph

Mathematics
1 answer:
ivanzaharov [21]3 years ago
6 0

Answer:

option 1

Step-by-step explanation:

formula:(x-h)^(2)*(y-k)^(2)=r^2

well if you move the circle 3 units left h is (-3), plug it in, you get 3, so it is (x+3)^2*(y-k)^(2)=r^2

if you move the circle 2 units up, plug it in you get (-2), so it is

(x+3)^2*(y-2)^(2)=r^2

now, the radius is 3 (we can see from the graph) so radius ^2 is 9, thus

(x+3)^2*(y-2)^(2)=9

this is the answer, and the option that has it is answer is option 1

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3 years ago
Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1
jek_recluse [69]

Answer:

S_{31}=71.3


Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

U_n=a_1+(n-1)d


We were given that the 9th term is 17.


\Rightarrow 17=a_1+(9-1)(-2.1)


\Rightarrow 17=a_1+(8)\times(-2.1)


\Rightarrow 17=a_1-\frac{84}{5}


\Rightarrow 17+\frac{84}{5}=a_1


\Rightarrow a_1=\frac{169}{5}


The sum of the first n-terms is given by the formula,


S_n=\frac{n}{2}(2a_1+(n-1)d)


To find S_{31}, we substitute n=31, a_1=\frac{169}{5} and d=-2.1.


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))


\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))



\Rightarrow S_{31}=\frac{31}{2}(\frac{23}{5})


\Rightarrow S_{31}=\frac{713}{10}


\Rightarrow S_{31}=71.3


The correct answer is D















8 0
3 years ago
Read 2 more answers
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nikitadnepr [17]

Answer:

D

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2 years ago
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a).

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b).

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