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Paladinen [302]
3 years ago
15

Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.

After 9 hours of burning, a candle has a height of 24.5 centimeters. After 23 hours of burning, its height is 17.5 centimeters. What is the height of the candle after 21
hours?
___ centimeters
Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Suppose that the height (in centimeters) of a candle is a linear function of

the amount of time (in hours) it has been burning.

Let x be the amount of time in hours

Let y be the heoght of a candle in centimeters

The two points are then as (9,24.5) and (23,17.5).

\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(9,\:24.5\right)\mathrm{,\:}\left(23,\:17.5\right)

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(9,\:24.5\right),\:\left(x_2,\:y_2\right)=\left(23,\:17.5\right)

m=\frac{17.5-24.5}{23-9}

m=-0.5

\mathrm{Plug\:the\:slope\:}-0.5\mathrm{\:into\:}y=mx+b

y=\left(-0.5\right)x+b

\mathrm{Plug\:in\:}\left(9,\:24.5\right)\mathrm{:\:}\quad \:x=9,\:y=24.5

24.5=\left(-0.5\right)\cdot \:9+b

24.5=\left(-0.5\right)\cdot \:9+b

-4.5+b=24.5

b=29

\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=-0.5\mathrm{\:and\:}\mathbf{b}=29

y=-0.5x+29

Now plug in x=21, we get

y=-0.5*21+29=18.5

Thus the height of the candle after 21 hours is 18.5 centimeters.

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