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nikdorinn [45]
3 years ago
12

Please help me this is due tonight

Mathematics
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

  B = (2, -5)

Step-by-step explanation:

The problem requirements mean ...

  B - A = (2/3)(C - A)

  B = A + (2/3)C - A

  B = (1/3)A + (2/3)C = (A +2C)/3

  B = ((-6, 1) +2(6, -8))/3 = (-6+12, 1-16)/3 = (6, -15)/3

  B = (2, -5)

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2 years ago
The quotient of 4 and 1/5 will be greater than 4.
bixtya [17]
First, we will need to compute the quotient of 4 and 1/5
When we divide a number by a fraction, we convert the division to multiplication and then flip this fraction.
Therefore, in the given:
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Comparing this quotient to 4, we will find that the quotient is greater than 4

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Step-by-step explanation:

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2 years ago
PLEASE HELP!!! ASAP!!!!!!!!!!!!!!! 10 POINTS
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1800|2\\.\ 900|2\\.\ 450|2\\.\ 225|5\\.\ \ 45|5\\.\ \ \ 9|3\\.\ \ \ 3|3\\.\ \ \ 1|\\\\1880=2\cdot2\cdot2\cdot5\cdot5\cdot3\cdot3=2^3\cdot5^2\cdot3^2\\\\Answer:\ \boxed{2^3\cdot3^2\cdot5^2}

\sqrt[3]{320}\\\\320|2\\160|2\\.\ 80|2\\.\ 40|2\\.\ 20|2\\.\ 10|2\\.\ \ 5|5\\.\ \ 1|\\\\320=2\cdot2\cdot2\cdot2\cdot2\cdo2\cdot5=2^3\cdot2^3\cdot5=2^3\cdot2^3\cdot\\\\\sqrt[3]{320}=\sqrt[3]{2^3\cdot2^3\cdot5}=\sqrt[3]{2^3}\cdot\sqrt[3]{2^3}\cdot\sqrt[3]{5}=2\cdot2\sqrt[3]{5}=4\sqrt[3]5\\\\Answer:\ \boxed{\sqrt[3]{320}=4\sqrt[3]{5}}
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3 years ago
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