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Mariana [72]
2 years ago
5

Please help asap, 20 points

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
7 0

Solving for each equation:

A: True.

\frac{n}{2} +3 *4 = \frac{n}{2}+12\\\\\frac{n}{2} + 12 = \frac{n}{2} + 12

B: False.

\frac{1}{3}z+\frac{2}{3}z * 9 = 9z\\\\\frac{1}{3} z+6z = 9z

C: True, given that y = 1

-8y +4.3y + 3.7 = 0\\\\-3.7y = -3.7

D: True, given that b = 6.66667

12-1.8b+1.8b=1.8b\\12 = 1.8b

E: True.

\frac{m}{8} + 7(\frac{m}{8} ) =m\\\\\frac{m}{8} + (\frac{7m}{8} )= m\\\\\\\frac{8m}{8} = m\\

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Given that f(–2.4) = -1 and f(-1.9) = -8, approximate<br> f'(-2.4).<br> f'(-2.4)
lora16 [44]

Answer:

f'(-2.4) ≈ -14

General Formulas and Concepts:
<u>Algebra I</u>

Coordinate Planes

  • Coordinates (x, y)

Slope Formula: \displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}

Functions

  • Function Notation

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Step-by-step explanation:

*Note:

The definition of a derivative is the slope of the <em>tangent</em> <em>line</em>.

<u>Step 1: Define</u>

<em>Identify.</em>

f(-2.4) = -1

f(-1.9) = -8

<u>Step 2: Differentiate</u>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>.

  1. [Derivative] Set up [Slope Formula]:                                                           \displaystyle f'(-2.4) \approx \frac{f(x_2) - f(x_1)}{x_2 - x_1}
  2. Substitute in coordinates:                                                                           \displaystyle f'(-2.4) \approx \frac{-8 - -1}{-1.9 - -2.4}
  3. Evaluate:                                                                                                       \displaystyle f'(-2.4) \approx -14

---

Learn more about derivatives: brainly.com/question/17830594

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

6 0
2 years ago
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