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mr Goodwill [35]

3 years ago

15

A soft drink company bottles and sells lemon iced tea. They mix 15 gallons of lemonade with 8 gallons of tea and then pour the m

ixture into pint sized bottles. How many pint sized bottles will this mixture produce?

1 answer:

Ket [755]3 years ago

6 0

Answer:

<u>Thus this mixture contains 184 pints of Zesty lemon tea.</u>

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Determine whether the set is well defined. The set of children in first grade at Maple Elementary School who are boys. well defi

monitta

What does "well defined" mean to you, in this situation?

What makes up this set is very clear: "1st graders," "Maple Elem. School," "male." No ambiguity here. How does this relate to the concept of "well defined set?"

5 0

3 years ago

The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning c

uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

Who had the more convincing victory?

A. Roger had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is D

Step-by-step explanation:

From the question we are told that

The mean of the current year is $\mu_c = 186.32 \ minutes$

The standard deviation is $\sigma_c = 0.305 \ minutes$

The time taken by the winning car for the current year is $x = 185.85 \ minutes$

The mean of the previous year is $\mu_p = 110.7 \ minutes$

The standard deviation the previous year is $\sigma_p = 0.115 \ minutes$

The time taken by the winning car for the previous year is $y = 110.48 \ minutes$

Generally the z-score for current year is mathematically evaluated as

$z_c = \frac{x- \mu_c}{\sigma_c }$

=> $z_c = \frac{ 185.85- 186.32}{0.305 }$

=> $z_c = -1.536$

Generally the z-score for previous year is mathematically evaluated as

$z_p = \frac{y- \mu_p}{\sigma_p }$

=> $z_p = \frac{ 110.48-110.7}{0.115 }$

=> $z_p = -1.913$

From the value obtained we see that $z_p < z_c$ , Hence Karen had a more convincing victory because of the lower z -score.

5 0

3 years ago

The cost of renting a community center is $100, with an additional cost of $10 per guest.

Dennis_Churaev [7]

I can’t see it but if I had to say it would be D.

5 0

4 years ago

Solve for x and show work

jekas [21]

Answer:

x = 6

Step-by-step explanation:

Angle RPG = (Arc RQ + Arc SC)/2 Interior Secant Theorem

124 = (197 + 9x - 3)/2 Substitution

124 = (194 + 9x)/2 Alg

124 = 97 + 4.5x Alg

27 = 4.5x Alg

x = 6 Alg

Hope this helped! Ask me if you didn't understand something.

7 0

3 years ago

Country A has a growth rate of 2.2% per year. The population is currently 5,667,000, and the land area of Country A is 31,000,00

Akimi4 [234]

Answer:

It will be 290 years until there be one person for every square yard of land.

Step-by-step explanation:

We are looking for when the country's population is equivalent to its area in square yards: 31,000,000,000.

Write an equation for the situation: (Trickiest part)

p(x) = (5,667,000)(1 + 0.022)ˣ <= Can modify compound interest equation

31,000,000,000 = (5,667,000)(1 .022ˣ)

Started rounding off numbers

547.056 = 1 .022ˣ <= $x = \frac{log(ans)}{log(base)}$

Solve using log.

x = 2.738 / 0.00945 <= log(547.056) / log(1.022)

x = 289.7 <= Round up because rate is annual. Before the 290th year, the population is less than the number of square yards.

x = 290

Total amount with annual compound interest equation applied to this problem:

$A = P(1 + r)^{t}$ (Principle is starting investment)

Population = (Starting population)(1 + growth rate)^(time)

7 0

4 years ago