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vredina [299]
3 years ago
15

Point B (-1, -2) is the midpoint of line segment AC. Point A is located at (4,4). Find

Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Answer:

(-5, -8)

Step-by-step explanation:

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Write 5/10 in three equivalent forms
krek1111 [17]

equivalent fractions are fractions which have the same value.

equivalent fractions all have the same simplified form

we can write equivalent fractions by multiplying both numerator and denominator by the same number. We can also write equivalent fractions by dividing both numerator and denominator by the same number

so 5/10

we can get the equivalent fractions by multiplying by a common number

when we multiply by 2

\frac{5}{10}* 2= \frac{5*2}{10*2} = \frac{10}{20}

when we multiply by 3

\frac{5}{10}* 3 = \frac{5*3}{10*3} = \frac{15}{30}

when we multiply by 4

\frac{5}{10} *4 = \frac{5*4}{10*4}  = \frac{20}{40}

the three equivalent fractions are

10/20 , 15/30, 20/40

5 0
3 years ago
Read 2 more answers
Which inequality has the solution shown below?
olasank [31]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
Last week, Clay wrote 4 checks for $20 each from his checking account., withdrew another $30, and finally made a deposit of $96.
Aliun [14]
(4x20)+30=$110 taken out. if he had $96 put back in, then go $110-$96, leaving a balance of -$14, or in other words, the balance dropped $14.
6 0
3 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
You are constructing a tangent line from a point outside a given circle to the circle. You have drawn the circle, a point outsid
sveta [45]
Yikes I might go with C. 
6 0
3 years ago
Read 2 more answers
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