(2/3)-j
put it in parenthesis, the 2/3 to solve it correctly.
Answer:
Answer is on the pic
Step-by-step explanation:
I hope it's helpful!
![\bf \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{\pi r^2 h}{3}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{volume of a cylinder}}{V=24\pi }~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{24\pi }{3}}\implies V=8\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D%5Cpi%20r%5E2%20h%7D~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cone%7D%7D%7BV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D24%5Cpi%20%7D~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cone%7D%7D%7BV%3D%5Ccfrac%7B24%5Cpi%20%7D%7B3%7D%7D%5Cimplies%20V%3D8%5Cpi)
notice the volumes, the cone's volume is really one-third that of the cylinder, assuming "h"eight and "r"adius is the same on both.
Answer:
1/8
Step-by-step explanation:
I'm going to try to explain this as easy as possible. What I did was take the original shape and divide it by the new shape. For this question, I solved it by dividing 32(the original base) by 4(the new base) and got 8. So the scale factor of the reduction was 1/8.
