Here you go!........ I=1.48A
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Answer:
"1.079 kg/m3
"
Explanation:
yeah that could be the answer
Answer:
option D
Explanation:
given,
A conductor is carrying current = 2.0 A is 0.5 mm thick
Hall voltage = 4.5 x 10-6 V
uniform magnetic field = 1.2 T
density of the charge = n =?
hall voltage =
n = 6.67 × 10²⁷ charges/m
hence the correct answer is option D
The appropriate expression for the calculation of power by relating the angular energy in a given time.
In other words the instantaneous power of an angular accelerating body is the torque times the angular velocity
Where
Torque
Angular speed
Our values are given by
The angular velocity must be transformed into radians per second then
Replacing,
The average power delivered by the engine at this rotation rate is 211.1kW