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Helga [31]
3 years ago
8

1- ¿Cuál sería la energía de un objeto de 50 newton de peso que se encuentra sobre una estantería de 3 metros de altura? ¿Qué ti

po de Energía es?
Physics
1 answer:
Liula [17]3 years ago
6 0

Responder:

<h3>150 Nm </h3><h3>Energía potencial </h3>

Explicación:

El tipo de energía que posee el objeto se conoce como energía potencial. <u>La energía potencial es la energía que posee un objeto, mi virtud de su posición. </u>

Energía potencial = masa * aceleración debido a la gravedad * altura

Dado que Force = masa * aceleración debido a la gravedad

Energía potencial = Fuerza * altura

Fuerza dada = 50N y altura = 3 m

Energía potencial = 50 * 3

Energía potencial = 150 Nm

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Momentum of the 2 kg mass moving with velocity 10 m/s is *
gulaghasi [49]
20 kg*m/s because there is 2 kg mass and 10 m/s so you can multiply.
8 0
3 years ago
the candle had 350 J of energy in the chemical store. As it burned, 250 J was transferred by lighting to the surrounding​
Elan Coil [88]

Answer:

Efficiency = 71%

Explanation:

Given the following data:

Output energy = 250 Joules

Input energy = 350 Joules

To find efficiency;

Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100

Substituting into the equation, we have;

Efficiency = \frac {250}{350} * 100

Efficiency = 0.7143 * 100

Efficiency = 71.43 ≈ 71%

Therefore, the efficiency of the candle is 71 percent.

4 0
3 years ago
Water enters a student's house 10.0 m above the ground through a pipe with a cross section area of 1.00 x 10-4m2 at ground. Insi
dezoksy [38]

Answer:

(a). V₁ = 10m/s (velocity inside the house), V₂ = 5m/s (velocity at ground level)

(b). P₂ = 236500 Pa

Explanation:

This is quite straight-forward so let us begin by defining the terms given.

Given that;

The cross-section area inside the student's house A₁ = 0.50 0.50 x 10-4m2.

Let us make the velocity of water inside the house be V₁

such that the Volume of water entering the per second is = A₁V₁

Therefore, in 90sec:

45 L =  90 A₁V₁

V₁ = 45 * 10⁻³m³ / 90*0.5*10⁻⁴

V₁ = 10m/s            (velocity of water inside the house)

From the continuity equation we have that;

A₁V₁ = A₂V₂

0.5*10⁻⁴ * 10 = 1*10⁻⁴ V₂

V₂ = 5m/s               (velocity at ground level)

(b). We are told to calculate the water pressure in the pipeline at the ground level.

Using Bernoulli's equation;

P₁ + pgh₁ + 1/2PV₁²  (inside)      =       P₂ + pgh₂ + 1/2PV₂²   (ground level)

1.01*10⁵ + 1000*9.8*10 + 1/2*1000*(10)² = P₂ + 0 + 1/2*1000*(5)²

P₂ (pressure) = 1.01*10⁵Pa

Therefore we have;

101000 + 98000 + 50000 = P₂ + 12500

P₂ = 236500 Pa

cheers I hope this helped !!

3 0
3 years ago
How would you find the average speed of a cyclist throughout an entire race
pishuonlain [190]
<span>Velocity, you divide distance/time </span>
4 0
3 years ago
Traveling in circle requires a net force
seraphim [82]

Answer:

<u><em>Circular motion requires a net inward or "centripetal" force. Without a net centripetal force, an object cannot travel in circular motion. In fact, if the forces are balanced, then an object in motion continues in motion in a straight line at constant speed.</em></u>

Explanation:

3 0
3 years ago
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