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Gekata [30.6K]
3 years ago
15

What number could replace p below?p/4=6/8​

Mathematics
2 answers:
natali 33 [55]3 years ago
4 0

Answer:

p=3

Step-by-step explanation:

Using cross products

p/4=6/8​

8*p = 4*6

8p = 24

Divide each side by 8

8p/8 = 24/8

p =3

Marrrta [24]3 years ago
3 0

Answer:

3

Step-by-step explanation:

6/8 simplified is 3/4

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Can someone help please:<br> let f(x)=x^2+x <br> solve f(x-1)+f(x+1)=6
eimsori [14]

Step-by-step explanation:

f(x)=x^2+x

so

f(x-1) = (x - 1) ^ 2 + (x - 1)

= x^2 - 2x + 1 + x - 1

= x^2 - 3x

and

f(x+1) = (x + 1) ^ 2 + (x + 1)

= x^2 + 2x + 1 + x + 1

= x^2 + 3x + 2

now

f(x-1) + f(x+1) = 6

x^2 - 3x + x^2 + 3x + 2 = 6

2x^2 = 4

X = √2

brainliest pls took long enough to solve

5 0
3 years ago
Help please with easy geometry
netineya [11]

Answer:

Vertical line of symmetry

8 0
3 years ago
Read 2 more answers
Determine which set of numbers can be the lengths of the sides of a triangle.
prisoha [69]

Answer:

A) 13, 10, 16

Step-by-step explanation:

The Triangle Inequality Theorem will help you solve this question. The Triangle Inequality Theorem states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side.

The options that are given are:

  • A) 13, 10, 16
  • B) 1, 2, 3
  • C) 5.2, 11, 4.9
  • D) 208, 9, 219

Lets solve each one to figure out if they could be the lengths of a triangle.

A) 13, 10, 16.

We can write three inequalities to see if the lengths are true.

13 + 10 > 16

10 + 16 > 13

13+ 16 > 10

Solve each one.

23 > 16

26 > 13

29 > 10

According to the information above, the set of numbers from option A does  fit the Triangle Inequality Theorem. Therefore, they are possible lengths.

B) 1, 2, 3

Write three inequalities:

1 + 2 > 3

2 + 3 > 1

3+ 1 > 2

Solve each.

3 > 3

5 > 1

4 > 2

As you see, only two lengths fit the theorem, but the third side (3 > 3) does not. This set of lengths is not a possible set for a triangle.

C) 5.2, 11, 4.9

Write three inequalities:

5.2 + 11  > 4.9

4.9 + 11 > 5.2

5.2 + 4.9 > 11

Solve each.

16.2 > 4.9

15.9 > 5.2

10.1 > 11

As you see, only two sides lengths can repsent the lengths of a triangle but the third does not, so its not a possible set of lengths for a triangle.

D) 208, 9, 219

Write three inequalities:

208 + 9 > 219

219 + 9 > 208

208+ 219 > 9

Solve each.

217 > 219

228 > 208

427 > 9

Although two lengths fit the theorem, one length does not, so this a not a possible set of lengths.

In summary, only one set of lengths is possible for a triangle, with is A.

4 0
3 years ago
*CLICK THE PHOTO*
ELEN [110]

Answer:

$20.41

Step-by-step explanation:

1. 42.7/11.1 = 3.85

2. 5.30 times 3.85= 20.41

3. $20.41

7 0
3 years ago
Which sets of ordered pairs represent relations that are functions? You may choose more than one correct answer.
Rudik [331]
{(1, 0), (2, 0), (3, 0), (4, 0)}
{(1, 1), (2, 2), (3, 3), (4, 4)}
{(6, -6), (-6, 6), (5, -5), (-5, 5)}
These are all functions.

8 0
3 years ago
Read 2 more answers
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