second-period class average:
55+70+450+480+170+270+95 = 1590
1590/20 = 79.5
sixth-period class average:
65+225+480+595+270+190 = 1825
1825/20 = 91.25
on average, students in the sixth period class scored higher
Answer:
D
Step-by-step explanation:
Given that the coordinates of the point A is (2,7) and the coordinates of the point B is (6,3)
We need to determine the midpoint of A and B
Midpoint of A and B:
The midpoint of A and B can be determined using the formula,
Substituting the points (2,7) and (6,3) in the above formula, we get;
Adding the numerator, we have;
Dividing the terms, we get;
Thus, the midpoint of the points A and B is (4,5)
Message me if you need anything else I’ll be happy to help.
What you see in the z score table is P(z< a constant), for P( z≥ a number), subtract the probability from 1:
1-0.1587=0.8413
on the z score table, you will see that p(z<1.00)=0.8413
so c=1.00
