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insens350 [35]
3 years ago
6

F(x) x^2-2x+3= -2x+ 28

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

x₁ = - 5, x₂ = 5

Step-by-step explanation:

x^2 + 3 = 28

x^2 = 28 - 3

x^2 = 25

x = ± 5

x = - 5

x = 5

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A total of 937 people attended the play.
insens350 [35]

Answer:

1.75

c

+

2.25

a

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1083.00

now we still know, that

a

=

508

−

c

so we can substitute it into the second formula

1.75

c

+

2.25

(

508

−

c

)

=

1083

now its just simple algebra

1.75

c

+

1143

−

2.25

c

=

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60

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so:

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120

Step-by-step explanation:

6 0
3 years ago
If x is divided by 5 the remainder is 4. If why is divided by 5 the remainder is 1. What is the remainder when x+y is divided by
Naddik [55]

Answer:

0

Step-by-step explanation:

We are given the following:

\frac{x}{5}=q_1+\frac{4}{5}      (equ. 1)

\frac{y}{5}=q_2+\frac{1}{5}      (equ. 2)

We are asked:

\frac{x+y}{5}=q_3+\frac{r}{5}  (equ. 3) , what is r?

The q_i's represent the quotients you get.

r is the remainder of dividing x+y by 5.

We know that r is a number in {0,1,2,3,4}.

x=5q_1+4 (I got this by multiplying both sides of equ 1. by 5.)

y=5q_2+1 (I got this by multiplying both sides of equ 2. by 5.)

Let's add these equations together:

x+y=(5q_1+5q_2)+(4+1)

Factoring the 5 out for the q_i's part and simplify 4+1 gives:

x+y=5(q_1+q_2)+5

So 5 can't be the remainder of dividing something by 5 but see that we can factor this right hand expression more as:

x+y=5(q_1+q_2+1)

So q_3=q_1+q_2+1 while there is no remainder (the remainder is 0).

Let's do an example if you are not convinced at this point that the remainder will be 0.

So choose x=9 since 9/5 gives a remainder of 4.

And choose y=16 since 16/5 gives a remainder of 1.

x+y=9+16=25 and 25/5 gives a remainder of 0.

8 0
3 years ago
Samantha earns $8 per hour at a candy store. She receives a 5% raise. What are her new hourly earnings?
d1i1m1o1n [39]
$8 x 5 = 40

40/100 = 0.4

$8 + 0.4 = $8.4

Therefore Samantha now earns $8.4 per hour.
4 0
3 years ago
A and b are positive integers and a–b = 3. Evaluate the following:
yulyashka [42]

1/27

1/27

125

Step-by-step explanation:

Given that,

a - b = 3

9^(1/2b) /3^a = 3^(2/2b) /3^a

= 3^b/3^a

= 3^(b-a)

= 3^(-3)

= 27^(-1)

= 1/27

27^(1/3b) /9^(1/2a) = 3^(3/3b) /3^(2/2a)

= 3^b/3^a

= 3^(b-a)

= 3^(-3)

= 27^(-1)

= 1/27

125^(1/3a) /25^(1/2b) = 5^(3/3a) /5^(2/2b)

= 5^a/5^b

= 5^(a- b)

= 5^3

= 125

6 0
3 years ago
Solve 58÷4(6×9)+7(7×3)<br><br>​
alina1380 [7]
Step:

58/4x54+7x21 =
783+7x21 =
783+147 =
930
8 0
3 years ago
Read 2 more answers
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