Answer:
26π
Step-by-step explanation:
Hmm... This one is a little hard to understand because of the LaTeX.
Any way, way back to the question. A useful piece of information:
<u>The formula for finding the circumference of a circle is 2πr or π · d :</u>
We first need to find out what x is.
Since 2 times the radius is the diameter, we can set up our equation like this:
2(x + 6) = 3x + 5
Solving gives:
2x + 12 = 3x + 5.
We subtract 2x from both sides:
+12 = x + 5
Subtract 5:
So x = 7.
Now we can plug-and-chug:
7 + 6 = 13 times 2pi (this is the radius)
21 + 5 = 26 times pi.
<u>Check:</u>
When we check 13 (radius) times 2 should equal the diameter(26)
13 * 2 = 26.
So we are correct. The answer 26π is correct.
1/2 is the answer. I hope this helps
Answer:
x = 15 or x = - 
Step-by-step explanation:
Cross- multiplying gives
(14x + 6)(17x + 5) = 9x(27x + 11) ( expanding factors )
238x² + 172x + 30 = 243x² + 99x
rearrange into standard form : ax² + bx + c = 0
5x² - 73x - 30 = 0 ← in standard form
consider the factors of the product 5 × - 30 = - 150 which sum to the coefficient of the x-term (- 73 )
the factors are - 75 and + 2
Use these factors to split the middle term
5x² - 75x + 2x - 30 = 0 ( factor by grouping )
5x(x - 15) + 2(x - 15) = 0 ← take out the factor (x - 15)
(x - 15)(5x + 2) = 0
equate each factor to zero and solve for x
x - 15 = 0 ⇒ x = 15
5x + 2 = 0 ⇒ x = -
Answer:
-8a times 1/9
Step-by-step explanation:
This can be thought of as -8a/1 times 1/9. (1/9 is the reciprocal of 9, so were just pulling the fraction apart)
By using the information you have, you can use make a proportion to solve this.
You burn 4 logs in 2 hours or 4/2. You are comparing this to your unknown number, x, over 8 hours. So it looks like this 4/2 = x/8. You read it as four logs in two hours is x logs in eight hours. To solve you cross multiply. You do 2 times x and 4 times eight. That would be 2x= 32. Your goal is getting x alone, so divide each side by 2. Your answer is x= 16 logs in eight hours. You can solve this different and maybe easier ways but this is the best way if you want to get used to going this in algebra. Hope that helps! :)
