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lys-0071 [83]
3 years ago
7

Find the zero of polynomial 7x+5

Mathematics
1 answer:
boyakko [2]3 years ago
4 0

Answer:

x=-5/7

Step-by-step explanation:

we have

f(x)=7x+5 ----> The degree of this polynomial is 1 (linear equation)

Remember that

The zero of the polynomial is the value of x when the value of f(x) is zero

so

For f(x)=0

0=7x+5

solve for x

x=-5/7 ----> the zero of the polynomial or x-intercept

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Factor by grouping.......
Gekata [30.6K]

Answer:

A. (7n-1) (8n-1)

Step-by-step explanation:

56n^2 -8n-7n+1

56n^2 -8n       -7n+1

Factor out 8n from the first group   and -1 from the second group

8n (7n-1)     -1(7n-1)

Factor out the (7n-1)

(7n-1) (8n-1)

7 0
3 years ago
What is 817.502 rounded to the nearest whole number?
kotegsom [21]
If a number has a decimal that is .5+, you round up. If it is .4-, you round down. So 817.502 would be 818.
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3 years ago
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A golfer hits a golf ball with a club. The mass of the ball is 0.05 kg.
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Answer:

100 N

Step-by-step explanation:

f= 0.05*2000=100 N

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3 years ago
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Find the value of cos 28°​cos 62°​– sin 28°​sin 62°​
Romashka [77]
<h2>Answer:</h2>

cos 28°​cos 62°​– sin 28°​sin 62°​ = 0

<h2>Step-by-step explanation:</h2>

From one of the trigonometric identities stated as follows;

<em>cos(A+B) = cosAcosB - sinAsinB             -----------------(i)</em>

We can apply such identity to solve the given expression.

<em>Given:</em>

cos 28°​cos 62°​– sin 28°​sin 62°​

<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>

A = 28°

B = 62°

<em>∴ Substitute these values into equation (i) to have;</em>

<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>

<em />

<em>Solve the left hand side.</em>

<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>

⇒ 0 = <em>cos28°cos62° - sin28°sin62°     (since cos 90° = 0)</em>

<em />

<em>Therefore, </em>

<em>cos28°cos62° - sin28°sin62° = 0</em>

<em />

<em />

8 0
2 years ago
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