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3 years ago

Tim says -40°f is equal to -40°c. explain why this is true.

2 answers:

5 0

$^{\circ}C=(^{\circ}F-32)\cdot\dfrac{5}{9}\\\\
^{\circ}C=(-40-32)\cdot\dfrac{5}{9}\\
^{\circ}C=-72\cdot\dfrac{5}{9}\\
^{\circ}C=-8\cdot5\\
^{\circ}C=-40$

Murljashka [212]3 years ago

4 0

Let C = degrees Celsius and F = degrees Fahrenheit $C = (F - 32) \times \frac{5}{9}\\\\$ $= (-40 - 32) \times \frac{5}{9}\\\\$ $= (-72) \times \frac{5}{9}\\\\$ $= -\frac{360}{9} \\\\$ $= -40$

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Can anyone help me with this qeustion I need it for math today.

Umnica [9.8K]

Answer:

Therefore

m∠Y = 41.1°

Step-by-step explanation:

Given:

In Δ YSE ,

m∠S = 70°

YE = 10 = side opposite to ∠Y

SE = 7 = side opposite to ∠S

To Find:

m∠Y = ?

Solution:

In Δ ABC, Sine Rule says

$\dfrac{a}{\sin A}= \dfrac{b}{\sin B}= \dfrac{c}{\sin C}$

So here In Δ YSE,

$\dfrac{YE}{\sin S}= \dfrac{SE}{\sin Y}= \dfrac{YS}{\sin E}$

substituting the given values we get

$\dfrac{10}{\sin 70}= \dfrac{7}{\sin Y}\\\\\sin Y=\dfrac{0.939\times 7}{10}=0.6577\\\\Y=\sin^{-1}0.6577=41.1\°$

Therefore

m∠Y = 41.1°

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4 years ago

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If your salary is $42,500 and your federal income taxes are 10% of your salary, how much money will you owe this year in federal

Zarrin [17]

I'm assuming that the salary is for the whole year. If it is not, do tell me.
Tax = 10/100 * 45000
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You owe $4500 in federal taxes.

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3 years ago

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slava [35]

Answer:

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0.22 hours per dollar

8.33 minutes per mile

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3 years ago

A = 4 0 0 1 3 0 −2 3 −1 Find the characteristic polynomial for the matrix A. (Write your answer in terms of λ.) Find the real ei

Illusion [34]

Answer:

Step-by-step explanation:

We are given the matrix

$A = \left[\begin{matrix}4&0&0 \\ 1&3&0 \\-2&3&-1 \end{matrix}\right]$

a) To find the characteristic polynomial we calculate $\text{det}(A-\lambda I)=0$ where I is the identity matrix of appropiate size. in this case the characteristic polynomial is

$\left|\begin{matrix}4-\lambda&0&0 \\ 1&3-\lambda&0 \\-2&3&-1-\lambda \end{matrix}\right|=0$

Since this matrix is upper triangular, its determinant is the multiplication of the diagonal entries, that is

$(4-\lambda)(3-\lambda)(-1-\lambda)=(\lambda-4)(\lambda-3)(\lambda+1)=0$

which is the characteristic polynomial of A.

b) To find the eigenvalues of A, we find the roots of the characteristic polynomials. In this case they are $\lambda=4,3,-1$

c) To find the base associated to the eigenvalue lambda, we replace the value of lambda in the expression $A-\lambda I$ and solve the system $(A-\lambda I)x =0$ by finding a base for its solution space. We will show this process for one value of lambda and give the solution for the other cases.

Consider $\lambda = 4$ . We get the matrix

$\left[\begin{matrix}0&0&0 \\ 1&-1&0 \\-2&3&-5 \end{matrix}\right]$

The second line gives us the equation x-y =0. Which implies that x=y. The third line gives us the equation -2x+3y-5z=0. Since x=y, it becomes y-5z =0. This implies that y = 5z. So, combining this equations, the solution of the homogeneus system is given by

$(x,y,z) = (5z,5z,z) = z(5,5,1)$

So, the base for this eigenspace is the vector (5,5,1).

If $\lambda = 3$ then the base is (0,4,3) and if $\lambda = -1$ then the base is (0,0,1)

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3 years ago