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3 years ago

Please help me. I been stuck for over an hour

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

Answer:

Step-by-step explanation:

P(a|b)= this mean the probability that a happens given that you already know b has occurred.

So for this P(work|senior) is the probability you will pick someone who works give you know they work. So you look for the over lap between seniors and work in the table and divide it by the number of seniors.

In this case:

P(Work | senior)= 5/(25+5+5) = 5/35 = 1/7

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The value of 25+144 is 13. O True O False

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30% of 50,400 = 30240.

Therefore the percentage loss is 30% over the course of 3 years.

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3 years ago

el jefe decidió agregar la tabla de frecuencias correspondiente a la edad de sus empleados tal Como se muestra a continuación Cu

lapo4ka [179]

Answer:

Average employee [Mean] = 43.6

Step-by-step explanation:

Given:

Interval Number of employee

25-35 20

35-45 7

45-55 8

55-65 15

Total 50

Find:

Average employee [Mean]

Computation:

Interval X[u+l]/2 Number of employee fx

25-35 30 20 600

35-45 40 7 280

45-55 50 8 400

55-65 60 15 900

Total 50 2,180

Average employee [Mean] = Sum of fx / Sum of x

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3 years ago

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Murrr4er [49]

Answer:

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Step-by-step explanation:

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3 years ago

Given the line y = − 2 5 x + 3, determine if the given line is parallel, perpendicular, or neither. Select the correct answer fo

stiks02 [169]

Answer:

(a) Neither

(a) Perpemdicular

Step-by-step explanation:

Required

Determine the relationship between given lines

(a)

$y = -\frac{2}{5}x + 3$

and

$y = \frac{2}{5}x + 7$

An equation written in form: $y=mx + b$ has the slope:

$m \to slope$

So, in both equations:

$m_1 = -\frac{2}{5}$

$m_2 = \frac{2}{5}$

For both lines to be parallel

$m_1 = m_2$

This is false in this case, because:

$-\frac{2}{5} \ne \frac{2}{5}$

For both lines to be perpendicular

$m_1 * m_2 = -1$

This is false in this case, because:

$-\frac{2}{5} * \frac{2}{5} \ne -1$

(b)

$5y + 2x = -10$

and

$-5x + 2y = 4$

Write equations in form: $y=mx + b$

$5y + 2x = -10$

$5y = -2x +10$

Divide by 5

$y = -\frac{2}{5}x +2$

$-5x + 2y = 4$

$2y = 5x + 4$

Divide by 2

$y = \frac{5}{2}x + 2$

In both equations:

$m_1 = -\frac{2}{5}$

$m_2 = \frac{5}{2}$

For both lines to be parallel

$m_1 = m_2$

This is false in this case, because:

$-\frac{2}{5} \ne \frac{5}{2}$

For both lines to be perpendicular

$m_1 * m_2 = -1$

This is true in this case, because:

$-\frac{2}{5} * \frac{5}{2} = -1$

Cancel out 2 and 5

$-1 = -1$

6 0

3 years ago