All categories

3 years ago

True or false? The degree of a binomial is always equal to 2

Mathematics

2 answers:

Anna35 [415]3 years ago

8 0

Answer:

It's False..........

wel3 years ago

4 0

Answer:

false

Step-by-step explanation:

the degree is found by looking at the term with the highest exponent of the variable..

You might be interested in

Find the area of the composite figure.

BARSIC [14]

Answer:

The total area is 132 ft squared

Step-by-step explanation:

I found the area of the triangle by doing bh/2 and got 60. I then found the read of the rectangle bu doing bh and got 72z I then added both areas and got 132 as the total area.

7 0

2 years ago

Read 2 more answers

½(4k + 3r) ÷ 3^1 k = 9 r = 6 show work

vampirchik [111]

Answer:

The solution is given below:

Step-by-step explanation:

$\\ \frac{1}{2} (4k + 3r) \div {3}^{1}$

As we know the value of k and r so the equation will be

$\\ \frac{1}{2} (4 \times 9 + 3 \times 6) \div {3}^{1}$

$\\ = \frac{1}{2} (36 + 18) \div 3$

$\\ = \frac{1}{2} \times 54 \div 3$

$\\ = \frac{1}{2} \times 18$

$\\ = 9$

3 0

2 years ago

Read 2 more answers

Pls help ASAP ‼️ will give brainliest

vlada-n [284]

Answer: 2592

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Given that a function, g, has a domain of -20 sxs 5 and a range of 5 s 39 s 45 and that g(0) = -2 and g(-9) = 6, select the stat

luda_lava [24]

Answer:

option (B) and (D)

Step-by-step explanation:

It's just basic of domain and range just check out the domain and range you can get your answer .

Only option (B) and (D) satisfy in the given range and domain

8 0

2 years ago

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

$(x-h) = 4p(y-k)^{2}$

$(x-4) = 4(\frac{-1}{12})(y+3)^{2}$

$(x-4) = \frac{-1}{3}(y+3)^{2}$

8 0

2 years ago