Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
The height of the enlarged picture will be 20 in because 15 divided by 6 is 2.5 so you multiply 2.5 by 8 in and you get 20.
Answer:
sorry don't know
Step-by-step explanation:
Answer:
a) 38
b) 19
Step-by-step explanation:
2πr = 119.32
2(3.14)r = 119.32
6.28r = 119.32
r = 119.32 / 6.28
r = 19
diameter = 2r = 2(19) = 38
Answer:The answer is true
Step-by-step explanation:
(I hope this helped you) :)
