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erastova [34]
3 years ago
10

Which statement correctly identifies structures 1 and 2 in the diagram?

Biology
2 answers:
8090 [49]3 years ago
8 0

Answer: structure 1 is an unstable atom structure 2 is a new atom

Explanation:

Vlada [557]3 years ago
5 0
Where are the diagrams
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What step number do you always start with when using a dichotomous key?
77julia77 [94]

Answer:

1

Explanation:

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The face says brainliest please!

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2 years ago
Imagine a diploid organism that has 6 pairs of homologous chromosomes in their somatic cells. Given
stich3 [128]

Answer:

A. False

B. False.

C. True.

D. False.

E. True

F. True

G. True

H. False.

Explanation:

Diploid organism has almost double the cells than in the Haploid. The number of chromosomes in each diploid cell are also nearly twice the other cells. Diploid is any cell or organism which has two sets of chromosomes. Gamete is considered as the sex cell. It has ability to pair up and formulate the reproductive cells.

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3 years ago
At which phase are centrioles beginning to move apart in animal cells?
nirvana33 [79]
Prophase is the answer 
6 0
3 years ago
QUICK help pleaseee needed by today
den301095 [7]
I think it is C because i got this same exact question in my class
8 0
3 years ago
Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the
erastova [34]

Complete question:

Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.

A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.

Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).

Answer:

The probability that the second child will also have the disease is 1/16.

Explanation:

<u>Available data:</u>

  • Two genes independently inherited: one for blood type, the other for disease
  • Man with type A blood  x  Woman with type B blood
  • Both parents are heterozygous for the gene that causes the disease; Dd

If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.

Cross:  

Parentals)           AiDd         x      BiDd

Gametes)  AD  Ad  iD  id       BD  Bd  iD  id

Punnett square)      AD       Ad       iD       id

                     BD   ABDD  ABDd  BiDD BiDd

                     Bd   ABDd   ABdd   BiDd Bidd

                     iD    AiDD    AiDd    iiDD   iiDd

                     id    AiDd     Aidd     iiDd    iidd

F1) <u>Genotype</u>:

1/16 ABDD

2/16 ABDd

1/16 ABdd

1/16 AiDD

1/16 BiDD

2/16 AiDd

2/16 BiDd

1/16 Aidd

1/16 Bidd

1/16 iiDD

2/16 iiDd

1/16 iidd

<u>Phenotype:</u>

3/16 A/B normal

4/16 A normal

4/16 B normal

3/16 0 normal

1/16 0 affected by the disease.

3 0
3 years ago
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