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lorasvet [3.4K]
3 years ago
13

Y 9. ΔΧΥΖ» Δ. ~^_ A. XYT; YZT B. XTY; YTZ C. TXY, ZYT Z T Х D. YXT; TYZ​

Mathematics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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A 2 foot wide painting should be centered on a 14 foot wide wall. How many feet (x) should be on each side of the painting?
geniusboy [140]

Divide the length of the wall by 2 to find the center of the wall:14/2 = 7 feet

The center of the painting is 2/2 = 1 foot.

The edge of the wall would be the center of the wall minus the center of the painting:

7 - 1 = 6 feet.

There should be 6 feet on each side of the painting.

4 0
3 years ago
72÷6374<br><img src="https://tex.z-dn.net/?f=72%20%5Cdiv%206374" id="TexFormula1" title="72 \div 6374" alt="72 \div 6374" align=
Ivan
72 divided by 6374 is equal to 0.0113

Hope it helps :)
6 0
3 years ago
Conditional Distribution, Marginal Distribution, Joint Distribution. <br> What’s the difference?
lutik1710 [3]

Explanation:

Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.

Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).

The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.

3 0
3 years ago
Please solve with explanation 8 points
11111nata11111 [884]

Answer:

See below.

Step-by-step explanation:

Given :-

x² + bx + c = 0 if x₁ + x₂ = -b and x₁x₂ = c

Solving :-

a) x₁ = 1/2 and x₂ = -3/4

=> x² + -(1/2 + -3/4)x + 1/2(-3/4)

=> x² + -(-1/4)x + (-3/8)

=> x² + 1/4x - 3/8

=> 8x² + 2x - 3 = 0

b) x₁ = 1 + √5 and x₂ = 1 - √5

=> x² + -(1 + √5 + 1 - √5)x + (1 + √5)(1 - √5)

=> x² - 2x + 1 - 5

=> x² - 2x - 4 = 0

3 0
2 years ago
Triangle ABC is transformed to triangle A′B′C′, as shown below:
Montano1993 [528]

Answer:

C. m<CAB = m<C'A'B'

Step-by-step explanation:

Triangle ABC looks like it was only reflected over the line y = 0. If the triangle was only reflected then the triangles should be congruent to each other.

3 0
2 years ago
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