A parallelogram has vertices (-3,4) (4,4)(2,-1) (-5,-1) on the coordinate plan what’s the area
1 answer:
Answer:
Area of this parallelogram: 35.
Step-by-step explanation:
What's the equation for the area A of a parallelogram?
A = b · h,
where
- b is the length of the base, and
- h is the length of the height <em>on that base</em>.
Plot the four vertices on a cartesian plane. Two opposite sides of this parallelogram are parallel to the x-axis. As a result, the length of the base is the same as the difference in x-coordinates between two vertices on that side. As seen on the diagram, the length of this base is b = 2 - (-5) = 7.
The height on either of those two sides will be normal to the x-axis and parallel to the y-axis. The length of those heights will be the same as the difference in y-coordinates between two vertices, one on each line. As seen on the diagram, the length of the height on base <em>b</em> is h = 4 - (-1) = 5.
Area of this parallelogram:
A = b · h = 5 × 7 = 35.
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Answer:
This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3
Step-by-step explanation:
The given function is
When we differentiate this function with respect to x, we get;
We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)
This implies that;
If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).
But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.