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natka813 [3]
3 years ago
12

A parallelogram has vertices (-3,4) (4,4)(2,-1) (-5,-1) on the coordinate plan what’s the area

Mathematics
1 answer:
Anon25 [30]3 years ago
4 0

Answer:

Area of this parallelogram: 35.

Step-by-step explanation:

What's the equation for the area A of a parallelogram?

A = b · h,

where

  • b is the length of the base, and
  • h is the length of the height <em>on that base</em>.

Plot the four vertices on a cartesian plane. Two opposite sides of this parallelogram are parallel to the x-axis. As a result, the length of the base is the same as the difference in x-coordinates between two vertices on that side. As seen on the diagram, the length of this base is b = 2 - (-5) = 7.

The height on either of those two sides will be normal to the x-axis and parallel to the y-axis. The length of those heights will be the same as the difference in y-coordinates between two vertices, one on each line. As seen on the diagram, the length of the height on base <em>b</em> is h = 4 - (-1) = 5.

Area of this parallelogram:

A = b · h = 5 × 7 = 35.

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How do you graph the equation f(x)=10x+40??
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Ok so linear equations come in the form
y = mx + b

B is the y-intercept. In this equation the y intercept is 40. A y- intercept is where the graph crosses the y axis so at the point (0,40) the graph crosses the y axis.

M is the slope which is rise over run so if the slope was 10 (which it is) 10 is equivalent to 10/1 so you move up 10 units for every 1 unit you move across.

So to graph this equation, you would draw your first point at (0,40). For your next point, you would move right one unit, and up 10 units. Draw a point there which would be (1, 50). Hopefully you understand. For going left from the y intercept point, you would move left 1 and down 10.

Actual graph above.

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