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Rudik [331]
2 years ago
15

The width of a dining room floor in a scale drawing is 6in. The actual width is 30 ft. What is the scale of the floor plan?

Mathematics
1 answer:
sasho [114]2 years ago
6 0

Answer:

Scale = 5ft/in

Step-by-step explanation:

Given

Scale Measurement = 6in.

Actual Width = 30ft

Required

Scale Ratio.

The scale ratio can be calculated as thus:

Scale Ratio = Actual Measurements ÷ Scale Measurements

Scale Ratio = 30ft ÷ 6in

Scale Ratio = 30ft/6in

Simplify to lowest terms

Scale Ratio = 5 ft/1 in

Scale Ratio = 5ft/in

This can also be represented as follows;

Scale Ratio = 5ft : 1in

This means that 5 ft on the actual measurements is represented by 1inch on the scale.

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In this truss bridge, AAOB ABDC. AO=5 meters, BD=10 meters, AB=5 meters. What is the length of BC? A. 5 m B. 8 m C. 10 m D. 15 m
Olenka [21]

Consider \Delta AOB\cong \Delta BDC.

Given:

\Delta AOB\cong \Delta BDC, AO=5\ m,BD=10\ m, AB=5\ m.

To find:

The length of BC.

Solution:

We have,

\Delta AOB\cong \Delta BDC

We know that the corresponding parts of congruent triangles are congruent (CPCTC).

AB=BC                   (CPCTC)

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2 years ago
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

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