Find the center and radius of a circle given the equation:
20%28y%20%2B%203%29%5E%7B2%7D%20%3D%20%5Cfrac%7B16%7D%7B9%7D" id="TexFormula1" title="(x - 2)^{2} + (y + 3)^{2} = \frac{16}{9}" alt="(x - 2)^{2} + (y + 3)^{2} = \frac{16}{9}" align="absmiddle" class="latex-formula">
1 answer:
Step-by-step explanation:
Equation of a circle is:
(x − h)² + (y − k)² = r²
where (h, k) is the center and r is the radius.
So in this case, the center is (2, -3) and the radius is 4/3.
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