Answer:
Index Fossils can be used to identify a specific time period.
Explanation:
Answer:
The answer D
Explanation:
The answer is in the question.
For staining flagella of bacteria use actively motile organisms 20 to 24 hours old, allow to diffuse in sterile water 20 to 30 minutes, transfer droplets of the suspension to clean slides and let evaporate without spreading. Then treat 2 to 4 minutes with the following mordant: tannic acid 10 or 20%, 50 cc.; ferric chloride 5%, 10 to 15 cc.; carbol fuchsin (Ziehl-Nielson), 5 cc.; hydrogen peroxide 3%, 6 to 8 cc. Wash and stain 2 to 3 minutes with a mixture of basic fuchsin, saturated alcoholic, 10 cc.; anilin oil (1 part) and 95% alcohol (3 parts) mixed, 5 cc.; distilled water, 30 cc.; acetic acid, 4%, 1 cc. Wash thoroly with water.
These cells have DNA in a region called the nucleoid.
-Some of these cells have structures like flagella and microvilli.
-These cells have cell walls made of polypeptides and polysaccharides.
Answer:
The correct answer is E. none of the above. The population will drops below 100 when t ≥ 38.
Explanation:
Given A= A0 e^kt. The population 10 years ago is A0, the population today is A(10), and we have to find the value of "k" and then the time when population drops below 100.
So, A(t) = 1700 e^kt ⇒ A(10) = 1700 e^k(10) ⇒ 800 = 1700 e^k(10) ⇒
800/1700 = e^k(10) ⇒ln (800/1700) = k(10) ln e ⇒ -0.754/10 = k ⇒
k = -0.0754.
Now you have all the parameters, so you can find the time at which the population drops below 100.
A(t) = 1700 e^kt ⇒ 100 = 1700 e^(-0.0754)t ⇒100/1700 = e^(-0.0754)t ⇒
ln(100/1700) = (-0.0754)t ln e ⇒ [ln(100/1700)]/(-0.0754) = t ⇒
t = 38.
So, the population will drops below 100 when t ≥ 38.
