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amm1812
2 years ago
8

Which is the equation of an ellipse with directrices at y = ±2 and foci at (0, 1) and (0, −1)?

Mathematics
1 answer:
Sedbober [7]2 years ago
6 0

Answer:

b) <em>Equation of the ellipse    </em>\frac{x^{2} }{1} + \frac{y^{2} }{2} = 1<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>step(i)</em></u>:-

<em>Given the direct rices of the ellipse   y = ±2</em>

<em>Given foci of the ellipse F( 0 ,± c) = ( 0,±1)</em>

<em>The  the direct rices of the ellipse </em>

                                              y = ±    \frac{a}{e}

                                               \frac{a}{e} = 2

                                               a = 2 e ...(i)

Given focus ( 0 , c) = ( 0, a e) = ( 0,1)

                                            a e = 1 ...(ii)

From (i) and (ii)

                                   2 e (e) = 1

                                   2 e² = 1

                                     e^{2} = \frac{1}{2}

                                     e = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

                         Now a = 2 e = 2 (\frac{1}{\sqrt{2} })

                                a  = √2

<em>Now we know that The relation between the focus and minor and major axes</em>

<em> formula  C² = a² - b²</em>

<em>                                             b² = a ² - C²</em>

<em>                                              b²  = 2 - 1 = 1</em>

<u><em>Step(iii)</em></u><em>:-</em>

<em>Equation of the ellipse</em>

<em>                                </em>\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} } = 1<em></em>

<em>                            </em>\frac{x^{2} }{1^{2} } + \frac{y^{2} }{(\sqrt{2}) ^{2} } = 1<em></em>

<em>                            </em>\frac{x^{2} }{1} + \frac{y^{2} }{2} = 1<em></em>

<u><em>Conclusion:</em></u><em>-</em>

<em>Equation of the ellipse    </em>\frac{x^{2} }{1} + \frac{y^{2} }{2} = 1<em></em>

<em></em>

<em>            </em>                          

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