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Lady_Fox [76]
3 years ago
15

Solve and check the following equation -15=5(3q-10)-5q

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

 q = 7/2 = 3.500

Step-by-step explanation:

   

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    5*(3*q-10)-5*q-(-15)=0

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (5 • (3q - 10) -  5q) -  -15  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  10q - 35  =   5 • (2q - 7)

Equation at the end of step  3  :

 5 • (2q - 7)  = 0

Step  4  :

Equations which are never true :

4.1      Solve :    5   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2      Solve  :    2q-7 = 0

Add  7  to both sides of the equation :

                     2q = 7

Divide both sides of the equation by 2:

                    q = 7/2 = 3.500

iren [92.7K]3 years ago
3 0

Answer:

The value of the equation is q=3.5.

Step-by-step explanation:

Consider the provide equation.

-15=5(3q-10)-5q

Open the parentheses

-15=15q-50-5q

Subtract the like terms.

-15=10q-50

Add 50 to the both sides.

-15+50=10q-50+50

35=10q

Divide both sides by 10.

q=3.5

Check.

Substitute q=3.5 in -15=5(3q-10)-5q

-15=5(3(3.5)-10)-5(3.5)

-15=5(10.5-10)-17.5

-15=5(0.5)-17.5

-15=2.5-17.5

-15=-15

Which is true.

Hence, the value of the equation is q=3.5

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Answer:

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Step-by-step explanation:

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iii) first withdrawal is given as $400

iv) second withdrawal is given as $400

v) third withdrawal is given as $400

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3 years ago
Two integers, a and b, have a product of 36. What is the least possible sum of a and b?
Minchanka [31]
<h3>Answer:  12</h3>

==============================================================

Explanation:

The two integers multiply to 36, so,

ab = 36

which solves to

a = 36/b

Then we want to add the numbers such that we get the smallest possible result.

a+b = (36/b)+b

So we want (36/b)+b to be as small as possible.

Let's say we replace b with x and we consider this function

f(x) = (36/x) + x

The goal is to find when f(x) is smallest, ie, we want to minimize the function.

If we were to graph out the function, we get the curve shown below.

To make things easier, we'll only focus on positive values of x.

The lowest part of the curve is what we're after. Using the "minimum" function/feature on the graphing calculator, we would then find the lowest point occurs at (6,12). This point is considered a local minimum because it's the lowest point in that given neighborhood of x values.

So the input x = 6 leads to the smallest output f(x) = 12.

This in turn means b = 6 is going to pair with a = 36/b = 36/6 = 6.

In short, a = 6 and b = 6.

----------------------

As a check,

a*b = 6*6 = 36

a+b = 6+6 = 12

We can make a table of various values to help confirm that 12 is the smallest sum.

Side note: If you're not allowed to use a graphing calculator, then you'll need to use calculus.

8 0
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