<u>ANSWER: </u>
If x = 
and x = -3 are the roots of the equation, then values of a and b are 3, -6
<u>SOLUTION:
</u>
Given, quadratic equation is 
and its roots are -3 ,
We know that, for any quadratic equation of form 
with roots 
then,
Sum of roots 
= 
Product of roots ( 
= 
Now, for given quadratic equation 
= -3 and 
=
hence Sum of roots = 
on solving we get "a" = 3
Now product of roots = 
b = -6
hence, the values of a and b are 3, -6.
Answer:
D. (4, 5)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 1
y = 1/2x + 3
<u>Step 2: Solve for</u><u><em> x</em></u>
- Substitute in <em>y</em>: x + 1 = 1/2x + 3
- Subtract 1/2x on both sides: 1/2x + 1 = 3
- Subtract 1 on both sides: 1/2x = 2
- Divide both sides by 1/2: x = 4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x + 1
- Substitute in <em>x</em>: y = 4 + 1
- Add: y = 5
<u>Step 4: Graph</u>
<em>We can confirm our answer.</em>
Answer:
81
Step-by-step explanation:
12(6) + 9
72 + 9
81......
Answer:
3/8
Step-by-step explanation:
three eighths I believe
-2 and 1.
Hope this helps!
