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2 years ago

4. CM Manufacturing has provided the following unit costs pertaining to a component they manufacture

Mathematics

1 answer:

TEA [102]2 years ago

3 0

uhh sorry i dont know

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Website A gets 5,000,000 hits in one day. Website B gets 4,000 hits in one day. Approximately how many times more hits does Webs

ArbitrLikvidat [17]

Answer:

<u>1,250</u> times more hits does Website A get than Website B.

Step-by-step explanation:

Given:

Website A gets 5,000,000 hits in one day.

Website B gets 4,000 hits in one day.

Now, to find the times more hits Website A get than Website B.

Website A gets hits in one day = 5,000,000.

Website B gets hits in one day = 4,000.

So, to get the number of times more Website A get than Website B we divide Website A gets hits in one day by Website B gets hits in one day:

$5,000,000\div 4,000$

$=1,250.$

Therefore, 1,250 times more hits does Website A get than Website B.

5 0

2 years ago

If your car travels 270 miles and uses 9.2 gallons, how many miles per gallon did you get? (Round your answer to three decimal p

leva [86]

270 miles divide by 9.2
29.348 miles per gallon

3 0

3 years ago

Read 2 more answers

Please answer asap. at my wits end with this test

riadik2000 [5.3K]

Answer:

Try photomath

Step-by-step explanation:

photomath might be the answer

5 0

2 years ago

Read 2 more answers

Write the number in scientific notation.<br> 1,920,000

KiRa [710]

The scientific notation is 1.92 x 10^6.

7 0

3 years ago

Exposure to ionizing radiation is known to increase the incidence of cancer. One thousand laboratory rats are exposed to identic

mojhsa [17]

Missing information :

The model was omitted from the question ; the possible model relating to the question was browsed online and could possibly be :

N(t) = 1.07t^2.3 for 0 ≤ t ≤ 10 months

Answer:

30.9 cases per month

Step-by-step explanation:

Given the model to determine the number of rats that have developed cancer after initial exposure ; N(t) = 1.07t^2.3

N(t) = 1.07t^2.3

Take the first derivative of N with respect to t to obtain the rate of change ;

N'(t) = (1.07)(2.3)t^2.3-1

N'(t) = (1.07)(2.3)t^1.3

The rate of growth of cancer cases at the 7th month can be calculated thus :

t = 7

N'(7) = (1.07)(2.3)t^1.3

N'(7) = 1.07 * 2.3 * 7^1.3

N'(7) = 1.07 * 2.3 * 12.549529

N'(7) = 30.884

The rate of growth of cancer at the 7th month is 30.9 cases per month.

7 0

3 years ago