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NNADVOKAT [17]
3 years ago
11

How do u work 9n=5? Just write it the way u worked it

Mathematics
2 answers:
8_murik_8 [283]3 years ago
8 0
Divide 5 by 9 to get 5/9

irina [24]3 years ago
4 0
If u want to switch one side doing multiplying to the other side, u have to change it to division
9n = 5
n = 5/9
n = 0.56 ( rounded to 2 dp)
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Answer to you’re question
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3 years ago
Suppose that a computer chip company has just shipped computer chips to a computer company.​ Unfortunately, of the chips are def
Varvara68 [4.7K]

Answer:

(a) 0.0000245

(b) 0.000025

Step-by-step explanation:

The complete question is:

Suppose that a computer chip company has just shipped 10,000 computer chips to a computer company. Unfortunately, 50 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) There are 50 defective chips out of 10,000 shipped. The probability that the first chip randomly selected is defective is  50 /10,000  = 0.005.  Compute the probability that two randomly selected chips are defective under the assumption of independent events.

Solution:

(a)

In this case we need to compute the conditional probability of selecting two defective chips, i.e. the selection of the second defective chip is dependent on the first defective chip.

The probability of selecting the first defective chip is:

P(1D)=\frac{50}{10000}=0.005

Now there are 9999 chips left and 49 defective chips among them.

The probability of selecting the second defective chip is:

P(2D)=\frac{49}{9999}=0.0049

Compute the probability that two randomly selected chips are defective using conditional probability as follows:

P (Two defective chips) =P(1D)\times P(2D)=0.005\times 0.0049=0.0000245

Thus, the answer is 0.0000245.

(b)

Compute the probability that two randomly selected chips are defective under the assumption of independent events as follows:

The above statement implies that the selection was done with replacement.

The probability is:

P (Two defective chips) =P(1D)\times P(2D)

                                      =\frac{50}{10000}\times \frac{50}{10000}\\\\=0.005\times 0.005\\\\=0.000025

Thus, the probability that two randomly selected chips are defective under the assumption of independent events is 0.000025.

6 0
3 years ago
Which statement is true about this equation?<br><br> -(2x+4)+x=3x-4x-4
Elodia [21]
That the equation could be combined into like terms
3 0
3 years ago
Jane corporation produces model toy cars each sells for $29 99 sense its variable cost per unit is $14 25 sense what is the brea
n200080 [17]

Answer:

Break-even point in units= 20,000

Step-by-step explanation:

Giving the following information:

Selling price per unit= $29.99

Unitary variable cost= $14.25

Fixed costs= $314,800

<u>To calculate the break-even point in units, we need to use the following formula:</u>

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 314,800 / (29.99 - 14.25)

Break-even point in units= 20,000

5 0
3 years ago
F - 3/4 = 1/2 what is f?
Julli [10]

Answer:

f=5/4

Step-by-step explanation:

f=1/2+3/4

f=(1/2)×2+3/4

f=2/4+3/4

f=5/4


3 0
3 years ago
Read 2 more answers
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