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daser333 [38]
3 years ago
8

HELP! ASAP! Five friends ate in a restaurant together and split the cost, c, equally. Each person paid less than $10. Which stat

ements represent the scenario? Check all that apply.
A. The situation can be represented using the inequality c ÷ 5 < 10.

B. The total cost of the food could be $40. The maximum total cost of the food could be determined by dividing 10 by 5.

C. When graphed, the number line would be shaded to the left of the maximum value.

D. The total cost of the food could be $50.
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0

Answer: A , B, C this is the correct answer

Scilla [17]3 years ago
6 0

Answer:

I know that A is correct

B the first part is correct, But the second part isnt.

C I dont know, not a good grapher

D would be correct if there was tax.

Step-by-step explanation:

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Given the formula a= 12.b, solve for a when b= 4.5
kaheart [24]

Answer:

a=54

Step-by-step explanation:

Because the problem gives you the value of b simply plug it in the equation a=12b. The new equation should look like this when plugged in: a=12(4.5). Now multiply 12*4.5=54. The new equation would then become a=54

6 0
3 years ago
Please Help<br><br>What is the solution for x in the equation?<br><br>9 − 10x = 2x + 1 − 8x<br>​
pashok25 [27]

Answer:

x=2

Step-by-step explanation:

4 0
3 years ago
which ordered pair is a solution to the system of linear equations 1/2 x - 3/4 y = 11/60 and 2/5 x + 1/6 y = 3/10?
bekas [8.4K]

Value of x=\frac{2}{3}\,\,and\,\,value\,\,of\,\,y=\frac{1}{5}

Solution set is  (\frac{2}{3},\frac{1}{5})

Step-by-step explanation:

We need to solve the following system of equations:

\frac{1}{2}x-\frac{3}{4}y=\frac{11}{60}\,\,\,eq(1)\\\frac{2}{5}x+\frac{1}{6}y=\frac{3}{10}\,\,\,eq(2)

We can solve this using Substitution.

Isolate x in \frac{1}{2}x-\frac{3}{4}y=\frac{11}{60}

\frac{1}{2}x=\frac{11}{60}+\frac{3}{4}y\\ x=\frac{11}{30}+\frac{3}{2}y

Putting value of x in equation(2)

\frac{2}{5}(\frac{11}{30}+\frac{3}{2}y)+\frac{1}{6}y=\frac{3}{10}\\Solving:\\Taking\,\,LCM\,\,of\,\,5,6,10 \,\,we\,\,get: 30\\Multiply\,\,by\,\,LCM\\\frac{2}{5}(\frac{11}{30}+\frac{3}{2}y)\times30+\frac{1}{6}y\times30=\frac{3}{10}\times30\\Simplifying:\\12(\frac{11}{30}+\frac{3}{2}y)+5y=9\\\frac{22}{5}+18y+5y=9\\23y=9-\frac{22}{5}\\23y=\frac{45-22}{5}\\23y=\frac{23}{5}\\y=\frac{\frac{23}{5} }{23}\\y=\frac{1}{5}

Putting value of y=1/5 in x=\frac{11}{30}+\frac{3}{2}y

x=\frac{11}{30}+\frac{3}{2}\times\frac{1}{5} \\x=\frac{11}{30}+\frac{3}{10}\\x=\frac{11+3*3}{30}\\x=\frac{11+9}{30} \\x=\frac{20}{30}\\x=\frac{2}{3}

So, value of x=\frac{2}{3}\,\,and\,\,value\,\,of\,\,y=\frac{1}{5}

Solution set is  (\frac{2}{3},\frac{1}{5})

Keywords: System of linear Equations

Learn more about System of linear Equations at:

  • brainly.com/question/9045597
  • brainly.com/question/13168205
  • brainly.com/question/2115716

#learnwithBrainly

5 0
4 years ago
Please help with my math test.
kati45 [8]
Answer is 30

Explanation: 5x6=30


EACH= MULTIPLY
5 0
3 years ago
Read 2 more answers
Students put 2 1/4 pounds of trail mix into bags that each weigh 3/8 pound. They bring 2/3 of the bags of trail mix on a hiking
mestny [16]

Total amount of trail mix which is poured into the bags = 2\frac{1}{4} pounds

= \frac{9}{4} pounds

Total amount of trail mix in each bag = \frac{3}{8} pound

Number of bags with  \frac{3}{8} pound, which can be poured from 2\frac{1}{4} pounds of trail mix

= Total amount of trail mix \div Amount of trail mix in each bag

= \frac{9}{4} \div \frac{3}{8}

= \frac{9}{4} \times \frac{8}{3}

= 6 bags

Number of bags taken on a hiking trip = \frac{2}{3} of bags

= \frac{2}{3} \times 6

= 4 bags

Now, number of bags of trail mix which are left = 6-4 = 2 bags.

Therefore, 2 bags are left.

6 0
3 years ago
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