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Veronica
3 years ago
0

When you have two shapes to compare on a coordinate plane?

you can determine the scale factor, knowing that the transformation was a dilation. Generate instructions you would give another student to determine the scale factor.
Mathematics
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Solve for X and find the length of EF.
DaniilM [7]

Answer:

X=1? and that would make EF= 15. But what are the choices?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The quadrilateral shown is a rectangle. What is the measure of PR? (round to the nearest hundredth) A) 34.06 B) 37.12 C) 40.24 D
Nata [24]

Answer: OPTION B.

Step-by-step explanation:

The missing figure is attached.

For this exercise you need to use the Pythagorean Theorem. This is:

a^2=b^2+c^2

Where "a" is the hypotenuse and "b" and "c" are the legs of the triangle.

In this case you can identify in the figure the triangle PRS, so the diagonal PR is the hypotenuse of the triangle PRS.

Then you can say that:

a=PR\\b=PS=17\\c=RS=33

Therefore, knowing these values, you can substitute them into a^2=b^2+c^2:

PR^2=17^2+33^2

Finally you must solve for PR in order to find its value. This is:

PR=\sqrt{17^2+33^2}\\\\PR=37.12

3 0
4 years ago
Find the measure of line segment MK. K 8 I 7 J M 5 2x+1<br>​
mrs_skeptik [129]

Hello!

This is a problem about relating circle theorems to line lengths.

We can first see that both line segment MK and CM are secants within the circle that come from a common point K.

This means that the Intersecting Secant Theorem applies here.

The Intersecting Secant Theorem states that if two secants are formed from a common point outside the circle, the length of each secant multiplied by the length of its corresponding external secant are equivalent.

We can set up the following equation.

8(8+x+5)=7(7+2x+1)

8(x+13)=7(2x+8)

8x+104=14x+56

6x=48

x=8

Using this value, we can find the length of line segment MK.

MK=x+5+8

MK=8+5+8

MK=21

Hope this helps!

5 0
3 years ago
Andre ran 2 kilometers in 15 minutes and Jada ran 3 kilometers in 20 minutes. Both ran at a constant speed. Did they run the sam
e-lub [12.9K]

Answer:

no, Andre ran at a sperm of 8km/hr while jada ran at 9km/hr you can find that by Andre going 2km in 15 minutes which turns to hours by multiplying by 4/4 to get 8/60 which 60 minutes is 1 hour then jada multiply by 3/3 which would be 9/60

5 0
3 years ago
PLEASE HELLLLLLLLLLLLLLP ME I NEED HELP PLEASE EXPLAIN HOW TO DO IT AS I HAVE A TEST NEXT WEEK AND IM REALLY STRESSED
Fynjy0 [20]

Answer:

C. Cos(60°) = Sin(30°)

Step-by-step explanation:

Cos(60°) = 0.5

Sin(30°) = 0.5

3 0
3 years ago
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