Which sequence has a common ratio of 2? a{20, 40, 80, 160, 320, 640, …} b{20, 10, 5, 2.5, 1.25, 0.625, …} c{20, 15, 10, 5, 0, -5
Elis [28]
Answer:
A
Step-by-step explanation:
40/20=2
80/40=2
Therefore the common ration is 2
<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
The number of cars that sold on the third week is (P3=26)
The number of cars that sold on the first week is (P4=33)
<u>Step-by-step explanation:</u>
<u>Given:</u>
- The number of cars that sold on the first week is (P0=7)
- The number of cars that sold on the second week is (P0=12)
We have to find the number of cars being sold on the upcoming week
From the data given above, frame the equation
Pn = Pn −1+7 ( 12-5=7 it denotes the cars sold in the first and the second week)
Pn=5+7n (cars in the first week and the cars sold in the second week into "n" n is used to find the cars sold in the upcoming weeks)
(If n=3)
Pn=5+7(3)
Pn=26
The number of cars that sold on the third week is (P3=26)
(If n=4)
Pn=5+7(4)
Pn=33
The number of cars that sold on the first week is (P4=33)
Answer:
Step-by-step explanation:
12 = 60% of x = 0.6x
x= 12/0.6= 20
Paper had 20 shapes. He cut out 12 shapes; 8 shapes remain
Answer:
x= 3/2 or 1.5
Step-by-step explanation:
First of all, you can take out the parenthesis because 8x is subtracting 2x-3.
8x-2x-3=12
6x-3=12
+3 +3
6x= 15
6x/6= 15/6
x= 3/2 or 1.5
Hope this helps!
