The length of the box would be 12288.
Answer:
D) cot(C) = 1/2.
Step-by-step explanation:
We can go through each choice and examine is validity.
Choice A)
We have:

Recall that secant is the ratio of the hypotenuse to the adjacent.
With respect to B, the adjacent is 6 and the hypotenuse is 7.
Therefore, sec(B) should be 7/6 instead.
A is incorrect.
Choice B)
We have:

Cotangent is the ratio of the adjacent side to the opposite.
With respect to B, the adjacent side is 6 and the opposite side is 3.
Therefore, cot(B) = 6/3 = 2.
B is incorrect.
Choice C)
C is incorrect for the reasons listed in A.
Choice D)
We have:

Again, cotangent is the ratio of the adjacent side to the opposite.
With respect to C, the adjacent side is 3 and the opposite side is 6.
So, cot(C) = 3/6 = 1/2.
Therefore, D is the correct choice!
Hiii :))
Answer is in the attachment.
Identity used :-
1) cosec² α = 1 + cot² α
Trigonometric Ratio :-
1) cot 30° = √3
_____
Reddam is an expensive school, right?
RainbowSalt2222 ☔
Answer:
THE ANSWER IS C
Step-by-step explanation:
BECAUSE BABABOOEEE
<u>Answer:</u>
x + y ≥ 26 + 15
5x + 8y ≥ 250 (see below)
Step-by-step explanation:
First, write an equation to represent the total cost to wash cars:
$5x = cost for cars
Then, write another for trucks:
$8y = cost for trucks
If the question is saying that they will wash at least 26 cars and 15 trucks, that means they could wash more. This means that we'll need an inequality:
This inequality represents that the total number of cars and trucks they wash will be at least—which means that it is equal to or greater than—than the amount given:
x + y ≥ 26 + 15
Any equation or inequality with two unknowns is not solvable, meaning we need a system of equations:
If they make at least $250, that means that we need to combine the costs of the cars and trucks to make an inequality:
5x + 8y ≥ 250
Now you have your system of equations:
x + y ≥ 26 + 15
5x + 8y ≥ 250