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jok3333 [9.3K]
3 years ago
14

PLEASEE answer correctly !!!!!!!!!!!!!! Show your workkkkk !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!

Mathematics
1 answer:
telo118 [61]3 years ago
3 0
The answer is 59
A triangle has 180 degrees. Subtract 62 from 180 to get 118, then divide by 2 to get the two angles on the bottom.
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Help!! Picking Brainliest! I need an answer fast...
IRISSAK [1]

3 * 5 = 15 miles during weekdays

6.5*2 = 13 miles on weekends

13 +15 = 28 miles total


28 / 7  = 4 miles average per day

6 0
3 years ago
A round trip flight from Seattle, Washington to Orlando, Florida is one of the longest flights in the continental United States.
ch4aika [34]
Time out =  d/so = d/523
time back = d/sb = d/415

t = time out + time back
11 = d/523 + d/415 find common deneminator
11 = (415d + 523d)/(523*415)
11*523*415 = 415d + 523d
2387495 = 938d
d = 2545 miles 

hope this help
6 0
3 years ago
Read 2 more answers
I don’t know how to do this lol this is a test
Artemon [7]

Answer:

D) x+y=-3

Step-by-step explanation:

Basically, if you plug in the x and y-coordinates into an equation, both sides should work out to be equal to each other:

Since -5+2\neq 3, we can eliminate choice A

Since -5-2\neq -3, we can eliminate choice B

Since -5-2\neq 3, we can eliminate choice C

Therefore, since -5+2=-3, then D is correct. Also, 3+(-6)=-3

3 0
2 years ago
Read 2 more answers
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
Please help me with this question :)​
klio [65]

Answer:

y>5/6

Step-by-step explanation:

5y+3>-7y+13

5y+7y>13-3

12y/12>10/12

y>5/6

This is an inequality, which shows where the variable y does or does not exist

from this we can say

y: (-infinity,5/6) (5/6, infinity]

or, y does not exist from (-infinity,5/6)

and does exist from (5/6, infinity]

3 0
2 years ago
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