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3 years ago

What is the factor of 15

Mathematics

2 answers:

Setler79 [48]3 years ago

8 0

The factor of 15 is 3, 5 because 3x5 is 15 and 5x3 is 15.

Butoxors [25]3 years ago

7 0

The factors of 15 is 5 and 3

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Pepsi [2]

Answer:

17/7 days will be the answer

Step-by-step explanation:

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3 years ago

A garden is 14 1/2 ft by 13 1/4 ft. What is the area

Marianna [84]

The area means to multiply the length by the width.

let's solve.

14 1/2 x 13 1/4.
convert our fractions into decimals.

14 1/2 = 14.50
13 1/4 = 13.25

Now we can multiply properly.

14.50 x 13.25 = 192.125
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Your area is:
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3 years ago

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tamaranim1 [39]

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3 years ago

Read 2 more answers

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

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