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tiny-mole [99]
3 years ago
15

Helppppppppppppppppppppppppppppp

Mathematics
2 answers:
stiv31 [10]3 years ago
6 0

Answer:

The person can correct this error two ways.  The first is by multiplying every part of the right side by 8 instead of only the \frac{y}{8}:

8(4) = (\frac{y}{8} + 1)(8)\\32 = y + 8\\24 = y

Another way to fix it is to subtract 1 from both sides before multiplying both sides by 8.

4 - 1 = (\frac{y}{8} + 1) - 1\\3 = \frac{y}{8} \\8(3) = \frac{y}{8}(8)\\24 = y

Please be sure to mark brainliest if this satisfies your question.

natita [175]3 years ago
4 0

Answer:

Step-by-step explanation:

4=y/8+1

rewrite equation

y/8 + 1 = 4

move all terms not containing y to the right of the equation

y/8 = 3

multiply both sides of the equation by 8

8 x y/8 = 8 x 3

simplify both sides of the equation.

y = 24

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3 years ago
Whats the cost of each vegetable if 5 squash and 2 zucchini is $1.32​
alex41 [277]

Answer:

Step-by-step explanation:

 

We first need to define a couple of variables.  Let s = the cost of 1 squash and z = the cost of 1 zucchini.

 

Now lets translate the words into algebra:

 

"The cost of 5 squash and 2 zucchini is $1.32"  ===>  5s  +  2z  =  1.32

 

"Three squash and 1 zucchini cost $0.75"  ===>   3s  +  z  =  0.75

 

There are several ways to solve systems of equations.  Let's use substitution.  We can find what z equals in terms of s by manipulating the second equation:

 

 3s  +   z   =   0.75

-3s                 -3s

------------     -------------

           z    =  -3s  +0.75

 

Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:

 

 5s + 2(-3s + 0.75) = 1.32

 

Can you handle it from here?

 

(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)

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