Hi, another math addition fraction question, please help.
2 answers:
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Answer:
0.3891 = 38.91% probability that only one is a second
Step-by-step explanation:
For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
17% of its goblets have cosmetic flaws and must be classified as "seconds."
This means that
Among seven randomly selected goblets, how likely is it that only one is a second
This is P(X = 1) when n = 7. So
0.3891 = 38.91% probability that only one is a second
Divide both sides by -2. We know that since 2 is negative, it'll be < (less than) 0. So, the direction of inequality will change.
Divide 26 by -2..we'll get the answer as -13.
Now, subtract 3 from both the sides.
Subtracting -13 by 3..we'll get the answer as -16.
Divide both sides by 2. We know that since 2 is positive, the direction of inequality will remain the same.
Divide -16 by 2..we'll get the answer as -8.
- The correct answer is ⇨ <u>x </u><u>greater </u><u>than </u><u>or </u><u>equal</u><u> to</u><u> </u><u>-</u><u>8</u><u>.</u>