Write the equation of a function whose parent function, F(x)=x+5,is shifted 3units to the right
2 answers:
Answer:
f'(x) = x + 2
Step-by-step explanation:
f(x) shift 3 units to the right -> f(x-3)
f'(x) = (x-3)+5 = x+2
Got this and not sure but best luck with your studying
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