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MatroZZZ [7]
3 years ago
7

During what month will the child reach 113 cm

Mathematics
1 answer:
Delicious77 [7]3 years ago
7 0
Do you need a more explanation of this problem to be entered
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Help !! Is the work shown in the simplification below correct? Explain.
melomori [17]
Try this solution:
1. rules:
cosec(t)= \frac{1}{sin(t)} ; \ sec(t)= \frac{1}{cos(t)} .
2. according to the rule described above:
\frac{cosec(t)}{sec(t)}= \frac{1}{sin(t)}: \frac{1}{cos(t)}= \frac{1}{sin(t)}* \frac{cos(t)}{1} = \frac{cos(t)}{sin(t)}=cotang(t).
6 0
3 years ago
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Select the correct answer from each drop-down menu.
Lunna [17]
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7 0
3 years ago
You are flying from Houston to Chicago. You leave Houston at 7:30 A.M. At 8:35 A.M. you fly over Little Rock, a distance of 455
Irina18 [472]

Answer:How long does it take to fly between Little Rock, AR and Houston, TX? Get the flight duration. Use the calculator to view a map and find flying times between cities. ... Supermodel Coco Rocha back on the runway just 3 months after giving birth ... you can use DistanceCalc.com to get the distance from Little Rock to Houston.

Step-by-step explanation:

7 0
3 years ago
Tickets to a school production cost $5 for a student ticket and $10 for an adult ticket. A total of 67 tickets were purchased at
vazorg [7]

Answer:

Step-by-step explanation:

Keywords:

System of equations, variables, cost, tickets, adults, children.

For this case we must solve a system of equations with two variables represented by the tickets of students and adults of a school production.

We define the variables according to the given table:

a: Number of tickets sold to adults

c: Amount of tickets sold to children.

We then have the following system of equations:

A + c = 67

10a + 5c =440

From the first equation, we clear the value of the variable c:

C = 67 - a

Answer:

The value that could replace c in the table is:

C = 67 - a

Option C is the answer!

Hope it helped u if yes mark me BRAINLIEST!

Tysm! Plz

9 0
3 years ago
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Question 18 (4 points)
Licemer1 [7]

for similar shapes, their corresponding sides will form the same proportion or ratio for any pair of corresponding sides, now, let's check the ratio of each corresponding side on these two.

\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \qquad \cfrac{12}{45}\implies \cfrac{4}{15}~\hfill \cfrac{25}{75}\implies \cfrac{1}{3}~\hfill \cfrac{15}{36}\implies \cfrac{5}{12} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{the triangles are \underline{not} similar}}{\cfrac{4}{15}\ne \cfrac{1}{3}\ne \cfrac{5}{12}}~\hfill

7 0
3 years ago
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