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3 years ago

I don't know how to solve but a small explanation would be nice

Mathematics

1 answer:

Blababa [14]3 years ago

7 0

Answer:

angle 1, 5, 7

Step-by-step explanation:

angle 3 = angle 1 (vertically opp angles)

angle 3 = angle 5 (alt angles, parallel lines)

angle 3 = angle 7 (corresponding angles, parallel lines)

Topic: angle properties

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-2x + 3y = 18. x = -y + 1

Bezzdna [24]

Answer:

D. X=-3, y=4

Step-by-step explanation:

-2x+3y=18 equation 1

x=-y+1 equation 2

-2(-y+1)+3y=18 replace x value of equation 2 into equation 1

2y-2+3y=18

5y=20

y=4

solve for x by replacing y value into either equation.

x=-y+1

x=-4+1

x=-3

8 0

3 years ago

Im giving 100 Points to anyone who could solve this for me please.

myrzilka [38]

Answer:

AB = 27.2

BC = 33.5

AC = 50.4

∠A = 38°

∠ABC = 112°

Step-by-step explanation:

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

$\implies \sf \cos(30^{\circ})=\dfrac{29}{BC}$

$\implies \sf BC=\dfrac{29}{\cos(30^{\circ})}$

$\implies \sf BC=\dfrac{58\sqrt{3}}{3}=33.5\:(nearest\:tenth)$

$\implies \sf \tan(30^{\circ})=\dfrac{BD}{29}$

$\implies \sf BD=29\tan(30^{\circ})$

$\implies \sf BD=\dfrac{29\sqrt{3}}{3}$

$\implies \sf \sin(38^{\circ})=\dfrac{BD}{AB}$

$\implies \sf AB=\dfrac{\dfrac{29\sqrt{3}}{3}}{\sin(38^{\circ})}$

$\implies \sf AB=27.2\:(nearest\:tenth)$

$\implies \sf \tan(38^{\circ})=\dfrac{BD}{AD}$

$\implies \sf AD=\dfrac{\dfrac{29\sqrt{3}}{3}}{\tan(38^{\circ})}$

$\implies \sf AD=21.4\:(nearest\:tenth)$

$\implies \sf AC=AD+DC=21.4+29=50.4$

The interior angles of a triangle sum to 180°

⇒ ∠A + 52° + 90° = 180°

⇒ ∠A = 180° - 90° - 52°

⇒ ∠A = 38°

⇒ ∠ABC + 38° + 30° = 180°

⇒ ∠ABC = 180° - 38° - 30°

⇒ ∠ABC = 112°

**I have checked the measures using a graphing programme - see attached**

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2 years ago

There is a proportional relationship between x and y complete the table with the missing values

Masja [62]

Answer: The first blank space is 45 and the one at the bottom is 10

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3 years ago

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4 years ago

Read 2 more answers

What is the distance, on a coordinate plane, between the points G(2.-3) and D(2, 4)?

Lady_Fox [76]

Answer:

Therefore ,the distance, on a coordinate plane, between the points G(2.-3) and D(2, 4) is $GD = 7\ units$

Step-by-step explanation:

Given:

point G( x₁ , y₁) ≡ ( 2 ,-3)

point D( x₂ , y₂) ≡ (2 , 4)

To Find:

Distance between GD=?

Solution:

Distance Formula between two point is given by

$l(GD) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting the values we get

$l(GD) = \sqrt{((2-2)^{2}+(4-(-3))^{2} )}$

$l(GD) = \sqrt{((0)^{2}+(4+3))^{2} )}=\sqrt{49}=7\\l(GD)=7\ units$

Therefore ,the distance, on a coordinate plane, between the points G(2.-3) and D(2, 4) is $GD = 7\ units$

8 0

3 years ago

I don't know how to solve but a small explanation would be nice​

I don't know how to solve but a small explanation would be nice